Introduction to Reasoning and Proof

Learn to think like a mathematician

You already know how to reason. Every time you figure out that it must have rained because the sidewalk is wet, or conclude that your friend is upset based on their short text replies, you are using the same logical thinking that mathematicians use. The difference is that mathematicians have developed a precise language and structure for this kind of reasoning, one that allows them to be absolutely certain about their conclusions. In this lesson, you will learn that language, and you will discover that the logical thinking you already do naturally can be sharpened into a powerful tool for proving mathematical truths.

Core Concepts

Two Ways of Thinking: Inductive and Deductive Reasoning

Imagine you are at a new restaurant. You try their pasta dish and it is delicious. You come back and try their pizza, also delicious. You try their salad, their soup, their dessert. All delicious. Based on this pattern, you conclude: “Everything at this restaurant is delicious.”

That is inductive reasoning. You observed specific examples and made a general conclusion based on those observations. Inductive reasoning is powerful and useful. It is how scientists form hypotheses and how we navigate daily life. But notice something important: no matter how many dishes you try, you cannot be 100% certain that every dish is delicious. There might be one you have not tried yet that is terrible.

Now consider a different scenario. You know that all items on the lunch special menu are $10. You also know that the pasta is on the lunch special menu. Therefore, the pasta costs $10. This conclusion is not just probable, it is absolutely certain (assuming your starting facts are true).

That is deductive reasoning. You started with general rules and applied them to reach a specific, guaranteed conclusion. Deductive reasoning is the backbone of mathematical proof. When mathematicians prove something, they are not saying “this is probably true based on patterns.” They are saying “this must be true, with complete certainty, because it follows logically from things we already know.”

Reasoning Type Direction Certainty Example
Inductive Specific to general Probable, not certain “I’ve seen 100 swans, all white, so all swans are white”
Deductive General to specific Certain (if premises are true) “All squares have 4 sides. This is a square. Therefore, it has 4 sides.”

Conjectures and Counterexamples

When you use inductive reasoning to form a general statement, that statement is called a conjecture. A conjecture is an educated guess, a claim you believe might be true based on evidence, but which has not yet been proven.

Here is a conjecture: “The sum of any two odd numbers is even.”

Is this true? Let us test some examples:

  • $1 + 3 = 4$ (even)
  • $5 + 7 = 12$ (even)
  • $11 + 15 = 26$ (even)

Every example works. But remember, inductive reasoning cannot give us certainty. To truly prove this conjecture, we would need deductive reasoning (which we will explore soon). However, we can use inductive reasoning another way: to disprove conjectures.

A counterexample is a single example that proves a conjecture false. You only need one. Consider this conjecture: “All prime numbers are odd.”

Let us think about this. Is 2 a prime number? Yes, its only factors are 1 and itself. Is 2 odd? No, it is even. That is it. The single counterexample of 2 completely destroys the conjecture. No matter how many odd primes exist (3, 5, 7, 11, 13…), the existence of just one even prime proves the conjecture false.

This is a beautiful asymmetry in mathematics:

  • To prove a conjecture true, you often need careful deductive reasoning
  • To prove a conjecture false, you just need one counterexample

Conditional Statements: The Language of Logic

Mathematical reasoning relies heavily on “if-then” statements, called conditional statements. These have a precise structure:

“If it is raining, then the ground is wet.”

The part after “if” is called the hypothesis (or premise). The part after “then” is called the conclusion.

  • Hypothesis: It is raining
  • Conclusion: The ground is wet

We often use variables to represent these parts. If we call the hypothesis $p$ and the conclusion $q$, we can write the conditional as “If $p$, then $q$” or symbolically as $p \rightarrow q$.

Understanding this structure is essential because mathematical proofs are chains of conditional statements. Each step says “if this is true, then that must be true,” building toward a final conclusion.

Converse, Inverse, and Contrapositive

Every conditional statement has three related statements that you should know. Let us start with our original:

Original (Conditional): If it is raining, then the ground is wet. $(p \rightarrow q)$

The converse switches the hypothesis and conclusion:

Converse: If the ground is wet, then it is raining. $(q \rightarrow p)$

Notice something important: the converse is not necessarily true even if the original is true. The ground could be wet because someone watered the lawn, or because of morning dew, or because a fire hydrant burst. The original statement and its converse are logically independent.

The inverse negates both parts:

Inverse: If it is not raining, then the ground is not wet. $(\neg p \rightarrow \neg q)$

Again, this is not necessarily true. It might not be raining right now, but the ground could still be wet from earlier rain.

The contrapositive both switches and negates:

Contrapositive: If the ground is not wet, then it is not raining. $(\neg q \rightarrow \neg p)$

Here is the key insight: the contrapositive is always logically equivalent to the original statement. If the original is true, the contrapositive must be true, and vice versa. Think about it: if rain always makes the ground wet, then finding dry ground means it cannot be raining.

Form Structure From “If raining, then wet”
Conditional If $p$, then $q$ If raining, then wet
Converse If $q$, then $p$ If wet, then raining
Inverse If not $p$, then not $q$ If not raining, then not wet
Contrapositive If not $q$, then not $p$ If not wet, then not raining

Remember: The conditional and contrapositive are logically equivalent. The converse and inverse are logically equivalent to each other, but not to the original.

Biconditional Statements

Sometimes a statement and its converse are both true. When this happens, we can combine them into a single biconditional statement using the phrase “if and only if.”

Consider this statement about angles: “An angle is a right angle if and only if it measures 90 degrees.”

This means two things are true:

  1. If an angle is a right angle, then it measures 90 degrees.
  2. If an angle measures 90 degrees, then it is a right angle.

The biconditional is written symbolically as $p \leftrightarrow q$, and it is true only when both the conditional and its converse are true.

Biconditionals often appear as definitions in mathematics. When you see “if and only if” (sometimes abbreviated “iff”), you know the relationship works both ways.

Laws of Logic: Building Chains of Reasoning

Two fundamental laws allow us to connect statements and build arguments.

Law of Detachment (Modus Ponens)

If you know that a conditional statement is true, and you know that the hypothesis is true, then you can conclude that the conclusion is true.

Symbolically: If $p \rightarrow q$ is true, and $p$ is true, then $q$ is true.

Example:

  • Statement 1: If a figure is a square, then it has four right angles.
  • Statement 2: Figure ABCD is a square.
  • Conclusion: Figure ABCD has four right angles.

This might seem obvious, but it is the fundamental logical move that powers all of mathematics.

Law of Syllogism (Chain Rule)

If you have two conditional statements where the conclusion of the first matches the hypothesis of the second, you can chain them together.

Symbolically: If $p \rightarrow q$ is true, and $q \rightarrow r$ is true, then $p \rightarrow r$ is true.

Example:

  • Statement 1: If it is Saturday, then I go to the farmer’s market.
  • Statement 2: If I go to the farmer’s market, then I buy fresh vegetables.
  • Conclusion: If it is Saturday, then I buy fresh vegetables.

This law allows us to build long chains of reasoning, where each link connects to the next.

Introduction to Proof Structure

A mathematical proof is a logical argument that demonstrates why a statement must be true. While there are many proof techniques (which you will explore in later lessons), all proofs share certain characteristics:

  1. They start with given information. These are facts or conditions you are allowed to assume.

  2. Each step follows logically from previous steps. Every statement you make must be justified, either as something given, a definition, a previously proven theorem, or a logical consequence of earlier statements.

  3. They end with the statement to be proven. The final step should be exactly the conclusion you were trying to establish.

  4. Every step has a reason. In formal proofs, you explicitly state why each step is valid.

Here is a simple example of proof structure:

Given: $m$ and $n$ are even integers. Prove: $m + n$ is even.

Proof:

Statement Reason
$m$ and $n$ are even integers Given
$m = 2a$ for some integer $a$ Definition of even
$n = 2b$ for some integer $b$ Definition of even
$m + n = 2a + 2b$ Substitution
$m + n = 2(a + b)$ Factoring
$a + b$ is an integer Closure of integers under addition
$m + n$ is even Definition of even

Each step builds on previous ones, every claim has a reason, and we arrive at exactly what we wanted to prove. This is the structure you will use throughout geometry and beyond.

Notation and Terminology

Term Meaning Example
Conjecture An educated guess based on observations “All primes greater than 2 are odd”
Counterexample A single example that disproves a conjecture 2 is prime but not odd
Conditional An “if-then” statement If $p$, then $q$
Hypothesis The “if” part of a conditional $p$ in “If $p$, then $q$”
Conclusion The “then” part of a conditional $q$ in “If $p$, then $q$”
Converse Switch hypothesis and conclusion If $q$, then $p$
Inverse Negate both parts If not $p$, then not $q$
Contrapositive Negate and switch If not $q$, then not $p$
Biconditional True in both directions $p$ if and only if $q$
Law of Detachment From $p \rightarrow q$ and $p$, conclude $q$ Modus Ponens
Law of Syllogism Chain conditionals together From $p \rightarrow q$ and $q \rightarrow r$, conclude $p \rightarrow r$
Proof A logical argument showing why a statement must be true See examples

Examples

Example 1: Identifying Hypothesis and Conclusion

Identify the hypothesis and conclusion in each conditional statement:

a) If a triangle has three equal sides, then it is equilateral.

b) If today is Wednesday, then tomorrow is Thursday.

c) You will pass the test if you study.

Solution:

a) Hypothesis: A triangle has three equal sides Conclusion: It is equilateral

b) Hypothesis: Today is Wednesday Conclusion: Tomorrow is Thursday

c) This one is tricky because the order is reversed. Rewriting it as “If you study, then you will pass the test”: Hypothesis: You study Conclusion: You will pass the test

Notice that in part (c), the word “if” still signals the hypothesis, even though it appears later in the sentence. Always look for “if” to find the hypothesis.

Example 2: Writing the Converse

Write the converse of each conditional statement. Then determine whether the converse is true or false.

a) If an animal is a dog, then it is a mammal.

b) If a number is divisible by 6, then it is divisible by 3.

c) If two angles are vertical angles, then they are congruent.

Solution:

a) Converse: If an animal is a mammal, then it is a dog. True or False? False. Cats, whales, and humans are mammals but not dogs.

b) Converse: If a number is divisible by 3, then it is divisible by 6. True or False? False. The number 9 is divisible by 3 but not by 6.

c) Converse: If two angles are congruent, then they are vertical angles. True or False? False. Two angles could both measure 45 degrees without being vertical angles (for instance, two angles in an isosceles right triangle).

These examples illustrate an important point: even when a conditional statement is true, its converse may be false. Never assume the converse is true without checking.

Example 3: Finding Related Conditionals and Truth Values

Consider the statement: “If a quadrilateral is a square, then it has four right angles.”

a) Write the converse, inverse, and contrapositive.

b) Determine whether each statement is true or false.

Solution:

a) Let $p$ = “a quadrilateral is a square” and $q$ = “it has four right angles.”

Original: If a quadrilateral is a square, then it has four right angles. $(p \rightarrow q)$

Converse: If a quadrilateral has four right angles, then it is a square. $(q \rightarrow p)$

Inverse: If a quadrilateral is not a square, then it does not have four right angles. $(\neg p \rightarrow \neg q)$

Contrapositive: If a quadrilateral does not have four right angles, then it is not a square. $(\neg q \rightarrow \neg p)$

b) Original: True. By definition, all squares have four right angles.

Converse: False. A rectangle has four right angles but is not necessarily a square (it might not have four equal sides).

Inverse: False. A rectangle that is not a square still has four right angles.

Contrapositive: True. This must be true because the original is true. If a quadrilateral is missing even one right angle, it cannot be a square.

Notice the pattern: the original and contrapositive have the same truth value, and the converse and inverse have the same truth value.

Example 4: Using the Law of Detachment

Use the Law of Detachment to draw a valid conclusion.

a) Statement 1: If a polygon has exactly three sides, then it is a triangle. Statement 2: Polygon XYZ has exactly three sides.

b) Statement 1: If the sum of two angles is 90 degrees, then the angles are complementary. Statement 2: Angle A measures 35 degrees and Angle B measures 55 degrees.

c) Statement 1: If it is raining, then the game will be cancelled. Statement 2: The game was cancelled.

Solution:

a) We have the conditional $p \rightarrow q$ where $p$ = “a polygon has exactly three sides.”

We are told that Polygon XYZ has exactly three sides. This confirms $p$ is true.

By the Law of Detachment: Polygon XYZ is a triangle.

b) First, let us check if the hypothesis is satisfied. Does $35° + 55° = 90°$? Yes, it does.

So the hypothesis “the sum of two angles is 90 degrees” is true.

By the Law of Detachment: Angle A and Angle B are complementary.

c) This is a common logical error to watch for. We know the conditional (if raining, then cancelled) and we know the conclusion (the game was cancelled).

No valid conclusion can be drawn using the Law of Detachment.

The game could have been cancelled for other reasons: equipment failure, a scheduling conflict, or just a decision by the organizers. The Law of Detachment only works when you know the hypothesis is true. Knowing the conclusion is true tells you nothing about the hypothesis.

Example 5: Building a Chain of Reasoning with the Law of Syllogism

Use the Law of Syllogism to write a chain of reasoning, then draw a final conclusion using the Law of Detachment.

Given statements:

  1. If a shape is a rhombus, then it is a parallelogram.
  2. If a shape is a parallelogram, then its opposite sides are parallel.
  3. If a shape has opposite sides parallel, then its opposite angles are equal.
  4. Shape ABCD is a rhombus.

What can you conclude about shape ABCD?

Solution:

First, let us identify the chain. Let:

  • $p$ = “a shape is a rhombus”
  • $q$ = “it is a parallelogram”
  • $r$ = “its opposite sides are parallel”
  • $s$ = “its opposite angles are equal”

We have:

  • Statement 1: $p \rightarrow q$
  • Statement 2: $q \rightarrow r$
  • Statement 3: $r \rightarrow s$
  • Statement 4: $p$ is true (ABCD is a rhombus)

Applying the Law of Syllogism:

From $p \rightarrow q$ and $q \rightarrow r$, we conclude $p \rightarrow r$. (If a shape is a rhombus, then its opposite sides are parallel.)

From $p \rightarrow r$ and $r \rightarrow s$, we conclude $p \rightarrow s$. (If a shape is a rhombus, then its opposite angles are equal.)

Applying the Law of Detachment:

We know $p \rightarrow s$ (If a shape is a rhombus, then its opposite angles are equal.) We know $p$ is true (ABCD is a rhombus).

Therefore: The opposite angles of ABCD are equal.

We can also conclude all the intermediate facts:

  • ABCD is a parallelogram.
  • The opposite sides of ABCD are parallel.

This example shows how the laws of logic allow us to build powerful chains of reasoning. Each link is guaranteed, so the final conclusion is just as certain as the starting facts.

Example 6: Evaluating a Conjecture

Consider the conjecture: “For any positive integer $n$, the expression $n^2 - n + 41$ always produces a prime number.”

a) Test this conjecture for $n = 1, 2, 3, 4, 5$.

b) Does this prove the conjecture? Why or why not?

c) Find a counterexample if one exists.

Solution:

a) Testing values:

  • $n = 1$: $1^2 - 1 + 41 = 1 - 1 + 41 = 41$ (prime)
  • $n = 2$: $2^2 - 2 + 41 = 4 - 2 + 41 = 43$ (prime)
  • $n = 3$: $3^2 - 3 + 41 = 9 - 3 + 41 = 47$ (prime)
  • $n = 4$: $4^2 - 4 + 41 = 16 - 4 + 41 = 53$ (prime)
  • $n = 5$: $5^2 - 5 + 41 = 25 - 5 + 41 = 61$ (prime)

b) No, this does not prove the conjecture. Testing specific examples uses inductive reasoning, which can suggest a pattern but cannot prove it holds for all cases. In fact, this formula produces primes for $n = 1$ through $n = 40$, which is remarkable, but that still does not constitute proof.

c) Finding a counterexample: Let us try $n = 41$: $$41^2 - 41 + 41 = 41^2 - 41 + 41 = 41^2 = 1681 = 41 \times 41$$

Since $1681$ has factors other than 1 and itself, it is not prime.

Therefore, $n = 41$ is a counterexample, and the conjecture is false.

This example beautifully illustrates the danger of inductive reasoning. A pattern can hold for many cases and still fail eventually. In mathematics, we need deductive proof for certainty.

Key Properties and Rules

If the original $(p \rightarrow q)$ is… Then the contrapositive $(\neg q \rightarrow \neg p)$ is…
True True
False False

The conditional and its contrapositive are logically equivalent. They always have the same truth value.

The converse $(q \rightarrow p)$ and inverse $(\neg p \rightarrow \neg q)$…
Are logically equivalent to each other
May or may not have the same truth value as the original

Law of Detachment

If you know:

  1. $p \rightarrow q$ is true (the conditional)
  2. $p$ is true (the hypothesis)

Then you can conclude:

  • $q$ is true (the conclusion)

Warning: You cannot use the Law of Detachment if you only know $q$ is true. Knowing the conclusion does not tell you anything about the hypothesis.

Law of Syllogism

If you know:

  1. $p \rightarrow q$ is true
  2. $q \rightarrow r$ is true

Then you can conclude:

  • $p \rightarrow r$ is true

This can be extended to any number of linked conditionals: $p \rightarrow q$, $q \rightarrow r$, $r \rightarrow s$, … leads to $p \rightarrow$ (final conclusion)

Biconditional Statements

A biconditional $p \leftrightarrow q$ is true only when:

  • $p \rightarrow q$ is true, AND
  • $q \rightarrow p$ is true

If either direction is false, the biconditional is false.

Proving vs. Disproving

To prove a universal statement (“for all…”) To disprove a universal statement
Must use deductive reasoning Just need one counterexample
Must cover all possible cases One exception is enough
Often requires careful proof Often requires creative thinking

Real-World Applications

Contracts are full of conditional statements. “If the buyer fails to make payment within 30 days, then the seller may terminate the agreement.” Legal arguments often involve analyzing whether the hypothesis of such a statement has been met, and therefore whether the conclusion applies. Lawyers use the Law of Detachment constantly: they establish that a conditional rule exists, then argue that the hypothesis is satisfied in their case.

The contrapositive also appears in legal reasoning. If a contract states “If you are an employee, then you must sign the confidentiality agreement,” the contrapositive tells us “If someone has not signed the confidentiality agreement, then they are not an employee.” This kind of reasoning helps establish facts.

Medical Diagnosis

Doctors use both inductive and deductive reasoning. Inductively, they notice patterns: “Several patients with these symptoms had this disease.” This leads to conjectures about diagnosis. Deductively, they apply known medical facts: “If a patient has symptom X and symptom Y, then they should be tested for condition Z.”

Medical reasoning also relies heavily on the contrapositive. If a certain disease always causes a particular marker in blood tests, then the absence of that marker rules out the disease.

Computer Programming

Programming is built on conditional logic. Every “if-then” statement in code is a conditional:

if (user_logged_in) {
    show_dashboard();
}

Programmers must think carefully about all four related forms. What happens if the user is not logged in (inverse)? What if someone is viewing the dashboard (converse)? Should someone not seeing the dashboard be assumed not logged in (contrapositive)?

The Law of Syllogism appears as chained conditionals: if A then B, if B then C, therefore if A then C. This is fundamental to how programs flow.

Scientific Method

Science uses inductive reasoning to form hypotheses based on observations. But a hypothesis is just a conjecture until it is tested. Scientists then try to find counterexamples. If they cannot disprove a hypothesis despite many attempts, it gains credibility. But unlike mathematics, scientific knowledge remains provisional. New evidence could always provide a counterexample.

The logical structure “If this theory is correct, then we should observe X” drives experimental design. Scientists use the contrapositive: if we do not observe X, the theory (in its current form) is incorrect.

Self-Test Problems

Problem 1: Classify each example of reasoning as inductive or deductive.

a) You notice that every time you water your plant on Sunday, it looks healthier on Monday. You conclude that watering on Sunday makes the plant healthier.

b) All mammals are warm-blooded. A whale is a mammal. Therefore, a whale is warm-blooded.

c) The first five prime numbers greater than 10 are all odd (11, 13, 17, 19, 23). You conclude that all prime numbers greater than 10 are odd.

Show Answer

a) Inductive reasoning. You are observing specific instances and making a general conclusion. The conclusion might be true, but it is not guaranteed. Perhaps the plant looks healthier for another reason.

b) Deductive reasoning. You start with a general rule (all mammals are warm-blooded) and apply it to a specific case (a whale). The conclusion is certain.

c) Inductive reasoning. You are generalizing from specific examples. (And this conjecture happens to be true, but the reasoning itself is inductive, not a proof.)

Problem 2: For the statement “If a number ends in 0, then it is divisible by 5”:

a) Identify the hypothesis and conclusion.

b) Write the converse, inverse, and contrapositive.

c) Determine the truth value of each statement.

Show Answer

a) Hypothesis: A number ends in 0 Conclusion: It is divisible by 5

b) Converse: If a number is divisible by 5, then it ends in 0.

Inverse: If a number does not end in 0, then it is not divisible by 5.

Contrapositive: If a number is not divisible by 5, then it does not end in 0.

c) Original: True. Any number ending in 0 is divisible by 5 (10, 20, 30, etc.).

Converse: False. The number 15 is divisible by 5 but ends in 5, not 0.

Inverse: False. The number 15 does not end in 0 but is divisible by 5.

Contrapositive: True. This must be true because the original is true. If you cannot divide a number by 5, it certainly does not end in 0.

Problem 3: Consider the conjecture: “The sum of any three consecutive integers is divisible by 3.”

a) Test the conjecture with three examples.

b) Can you find a counterexample?

c) Can you explain why this conjecture is true using variables?

Show Answer

a) Testing:

  • $1 + 2 + 3 = 6$, and $6 \div 3 = 2$ (divisible by 3)
  • $10 + 11 + 12 = 33$, and $33 \div 3 = 11$ (divisible by 3)
  • $(-1) + 0 + 1 = 0$, and $0 \div 3 = 0$ (divisible by 3)

b) No counterexample exists because the conjecture is true.

c) Let the three consecutive integers be $n$, $n+1$, and $n+2$.

Their sum is: $n + (n+1) + (n+2) = 3n + 3 = 3(n+1)$

Since $3(n+1)$ is 3 times an integer, it is always divisible by 3.

This algebraic argument is a deductive proof. Unlike the examples in part (a), it covers all possible cases.

Problem 4: Use the Law of Detachment or explain why no conclusion can be drawn.

a) If an angle measures less than 90 degrees, then it is acute. Angle ABC measures 47 degrees.

b) If it snows, then school will be cancelled. School was cancelled today.

c) If a triangle has two equal sides, then it has two equal angles. Triangle DEF has sides of length 5, 5, and 8.

Show Answer

a) We have $p \rightarrow q$ (if less than 90, then acute) and we know $p$ is true (47 < 90).

By the Law of Detachment: Angle ABC is acute.

b) We have $p \rightarrow q$ (if snow, then cancelled) and we know $q$ is true (school was cancelled).

No conclusion can be drawn. The Law of Detachment requires knowing the hypothesis is true. School could have been cancelled for other reasons (teacher workday, power outage, etc.).

c) We have $p \rightarrow q$ (if two equal sides, then two equal angles).

Triangle DEF has sides 5, 5, and 8. Two sides are equal (both are 5), so $p$ is true.

By the Law of Detachment: Triangle DEF has two equal angles.

Problem 5: Use the Law of Syllogism to combine these statements into a single conditional. Then, given that “Today is my birthday,” draw a final conclusion.

  • If today is my birthday, then I will have cake.
  • If I have cake, then I will be happy.
  • If I am happy, then I will smile.
Show Answer

Let:

  • $p$ = Today is my birthday
  • $q$ = I will have cake
  • $r$ = I will be happy
  • $s$ = I will smile

We have: $p \rightarrow q$, $q \rightarrow r$, $r \rightarrow s$

Applying the Law of Syllogism:

From $p \rightarrow q$ and $q \rightarrow r$: $p \rightarrow r$ (If today is my birthday, then I will be happy.)

From $p \rightarrow r$ and $r \rightarrow s$: $p \rightarrow s$ (If today is my birthday, then I will smile.)

Final conditional: If today is my birthday, then I will smile.

Applying the Law of Detachment:

Given: Today is my birthday ($p$ is true) And: $p \rightarrow s$ (If today is my birthday, then I will smile)

Conclusion: I will smile.

(We can also conclude the intermediate steps: I will have cake, and I will be happy.)

Problem 6: Write a biconditional statement for each pair if possible. If not possible, explain why.

a) Statement: If an integer is even, then it is divisible by 2. Converse: If an integer is divisible by 2, then it is even.

b) Statement: If a figure is a square, then it has four sides. Converse: If a figure has four sides, then it is a square.

Show Answer

a) Both the statement and converse are true. Being even and being divisible by 2 mean exactly the same thing for integers.

Biconditional: An integer is even if and only if it is divisible by 2.

b) The original statement is true (all squares have four sides), but the converse is false (a trapezoid has four sides but is not a square).

A biconditional cannot be written because the converse is false. For a biconditional to be valid, both the statement and its converse must be true.

Summary

  • Inductive reasoning uses specific observations to form general conclusions. It is useful for making conjectures but cannot provide certainty.

  • Deductive reasoning uses general principles to reach specific conclusions. When the premises are true, the conclusion is guaranteed.

  • A conjecture is an educated guess. A single counterexample is enough to disprove it.

  • Conditional statements have the form “If $p$, then $q$,” where $p$ is the hypothesis and $q$ is the conclusion.

  • Every conditional has three related statements:

    • Converse: Switch hypothesis and conclusion
    • Inverse: Negate both
    • Contrapositive: Switch and negate
  • The conditional and contrapositive are logically equivalent. The converse and inverse are equivalent to each other but independent of the original.

  • A biconditional ($p$ if and only if $q$) is true when both the conditional and its converse are true.

  • The Law of Detachment says: from $p \rightarrow q$ and $p$, conclude $q$.

  • The Law of Syllogism says: from $p \rightarrow q$ and $q \rightarrow r$, conclude $p \rightarrow r$.

  • Proofs are structured logical arguments where every step has a reason, building from given information to a conclusion.

These tools of logical reasoning are the foundation for everything else in geometry. When you understand how to construct and analyze logical arguments, you are ready to prove theorems, not just memorize them. You are learning to think like a mathematician.